[659] Still fork even if jobs == 1.

[Michael G Schwern]

Andy Armstrong wrote:
> On 3 Oct 2007, at 00:12, Michael G Schwern wrote:
>>> Still fork even if jobs == 1.
>>> With jobs == 0 it executes the forking code path but no forking  
>>> takes place inside Parallel::Iterator.
>> So --fork -j1 means what processes are doing what again?
> 
> Jobs == 0      : no forking
> Jobs == 1 .. n : fork that many workers

Sorry, I'm still confused.  I'm a bit lost in how the new parallel
implementation works.  What part is forking?  I presumed the TAP parser is
forking but then I don't understand why having one fork is useful.


-- 
Whip me, beat me, make my code compatible with VMS!